3.123 \(\int \frac {1}{\sqrt {-2+5 x+3 x^2}} \, dx\)

Optimal. Leaf size=35 \[ \frac {\tanh ^{-1}\left (\frac {6 x+5}{2 \sqrt {3} \sqrt {3 x^2+5 x-2}}\right )}{\sqrt {3}} \]

[Out]

1/3*arctanh(1/6*(5+6*x)*3^(1/2)/(3*x^2+5*x-2)^(1/2))*3^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {621, 206} \[ \frac {\tanh ^{-1}\left (\frac {6 x+5}{2 \sqrt {3} \sqrt {3 x^2+5 x-2}}\right )}{\sqrt {3}} \]

Antiderivative was successfully verified.

[In]

Int[1/Sqrt[-2 + 5*x + 3*x^2],x]

[Out]

ArcTanh[(5 + 6*x)/(2*Sqrt[3]*Sqrt[-2 + 5*x + 3*x^2])]/Sqrt[3]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 621

Int[1/Sqrt[(a_) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[2, Subst[Int[1/(4*c - x^2), x], x, (b + 2*c*x)
/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {-2+5 x+3 x^2}} \, dx &=2 \operatorname {Subst}\left (\int \frac {1}{12-x^2} \, dx,x,\frac {5+6 x}{\sqrt {-2+5 x+3 x^2}}\right )\\ &=\frac {\tanh ^{-1}\left (\frac {5+6 x}{2 \sqrt {3} \sqrt {-2+5 x+3 x^2}}\right )}{\sqrt {3}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 28, normalized size = 0.80 \[ \frac {\log \left (2 \sqrt {9 x^2+15 x-6}+6 x+5\right )}{\sqrt {3}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/Sqrt[-2 + 5*x + 3*x^2],x]

[Out]

Log[5 + 6*x + 2*Sqrt[-6 + 15*x + 9*x^2]]/Sqrt[3]

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fricas [A]  time = 1.03, size = 38, normalized size = 1.09 \[ \frac {1}{6} \, \sqrt {3} \log \left (4 \, \sqrt {3} \sqrt {3 \, x^{2} + 5 \, x - 2} {\left (6 \, x + 5\right )} + 72 \, x^{2} + 120 \, x + 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(3*x^2+5*x-2)^(1/2),x, algorithm="fricas")

[Out]

1/6*sqrt(3)*log(4*sqrt(3)*sqrt(3*x^2 + 5*x - 2)*(6*x + 5) + 72*x^2 + 120*x + 1)

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giac [A]  time = 0.73, size = 34, normalized size = 0.97 \[ -\frac {1}{3} \, \sqrt {3} \log \left ({\left | -2 \, \sqrt {3} {\left (\sqrt {3} x - \sqrt {3 \, x^{2} + 5 \, x - 2}\right )} - 5 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(3*x^2+5*x-2)^(1/2),x, algorithm="giac")

[Out]

-1/3*sqrt(3)*log(abs(-2*sqrt(3)*(sqrt(3)*x - sqrt(3*x^2 + 5*x - 2)) - 5))

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maple [A]  time = 0.04, size = 30, normalized size = 0.86 \[ \frac {\sqrt {3}\, \ln \left (\frac {\left (3 x +\frac {5}{2}\right ) \sqrt {3}}{3}+\sqrt {3 x^{2}+5 x -2}\right )}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(3*x^2+5*x-2)^(1/2),x)

[Out]

1/3*3^(1/2)*ln(1/3*(3*x+5/2)*3^(1/2)+(3*x^2+5*x-2)^(1/2))

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maxima [A]  time = 2.93, size = 28, normalized size = 0.80 \[ \frac {1}{3} \, \sqrt {3} \log \left (2 \, \sqrt {3} \sqrt {3 \, x^{2} + 5 \, x - 2} + 6 \, x + 5\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(3*x^2+5*x-2)^(1/2),x, algorithm="maxima")

[Out]

1/3*sqrt(3)*log(2*sqrt(3)*sqrt(3*x^2 + 5*x - 2) + 6*x + 5)

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mupad [B]  time = 0.23, size = 26, normalized size = 0.74 \[ \frac {\sqrt {3}\,\ln \left (\sqrt {3}\,\left (x+\frac {5}{6}\right )+\sqrt {3\,x^2+5\,x-2}\right )}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(5*x + 3*x^2 - 2)^(1/2),x)

[Out]

(3^(1/2)*log(3^(1/2)*(x + 5/6) + (5*x + 3*x^2 - 2)^(1/2)))/3

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {3 x^{2} + 5 x - 2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(3*x**2+5*x-2)**(1/2),x)

[Out]

Integral(1/sqrt(3*x**2 + 5*x - 2), x)

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